【文档说明】高考理数考前20天终极冲刺攻略： 算法初步 含答案解析.doc，共(13)页，732.000 KB，由MTyang资料小铺上传

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——IIII1..2..3..1..2.(1)..(2)..ABAB..ABABABAB..AB..3.1INPUT“”PRINT“”;12“”.34.2.1.2IF—THEN—ENDIF()IF—THEN—ELSE—ENDIF()..IF1THEN1ELSEIF2THEN2ELSE3E

NDIFENDIF.3.1.2UNTILWHILE1(2017Ⅰ8)321000nn−nAA>1000n=n+1BA>1000n=n+2CA≤1000n=n+1DA≤1000n=n+222017II81a=−S=A2B3C4D53(201

7III7)S91NA5B4C3D24.(2016III7)a=4b=6n=A3B4C5D65.(2016II8).x=2n=2a225s=A7B12C17D346.(2016I9)011xyn===xyA2

yx=B3yx=C4yx=D5yx=7.2015I9t=0.01n=A5B6C7D88.2015II8“”,ab14,18a=A0B2C4D1411,3t−sA2e,1−B1,eC01D2e,e−2ABCD3“”“”8A23B4

7C24D484ABCD5AB9C11D131()201720162018201721fxxxx=++++()0fxAni=B1ni=+Cn=2018i−Dn=2017i−2__________1.D321000nn−“”1000A1000An02nn=+D.2.

B1,1,0akS=−==.011,1,2Sak=−=−==121,1,3Sak=−+==−=132,1,4Sak=−=−==242,1,5Sak=−+==−=253,1,6Sak=−=−==363,1,7Sak=−+==−=3S=.B.3.D1,100,0tMS===tN100,10,12

10MSSMMtt=+==−=−=+=tN90,1,1310MSSMMtt=+==−==+=91SN2.4.B2,4,6,6,1abasn=====2,6,4,10abas=−===2n=2,4,6,16,3abasn=====2,6,4,2016,4abasn=−====4n=B5.C2,

2,0,0xnks====2a=0222,1sk=+==2a=2226,2sk=+==5a=62517,32sk=+==.17s=C.6.C0,1,1xyn===110,1112xy−=+==2236xy+2112,0,21222nx

y−==+===2236xy+13133,,236222nxy−==+===2236xy+3,62xy==,xy4yx=C.7.C1t=0.01,S=1,n=0,m=12=0.5,S=S−m=0.5,2mm==0.25,n=1,

S=0.5t=0.01,2S=S−m=0.25,2mm==0.125,n=2,S=0.25t=0.01,3S=S−m=0.125,2mm==0.0625,n=3,S=0.125t=0.01,4S=S−m=0.0625,2mm==0.03125,n=4,S=0.0

625t=0.01,5S=S−m=0.03125,2mm==0.015625,n=5,S=0.03125t=0.01,6S=S−m=0.015625,2mm==0.0078125,n=6,S=0.015625t=0.01,7S=S−m=0.0078125,2mm==0.0

0390625,n=7,S=0.0078125t=0.01,n=7C.8.Ba=14,b=18a<bb=18−14=4a=14,b=4a>ba=14−4=10a=10,b=4a>ba=10−4=6a=6,b=4a>ba=6−4=2;a=2,b=4a<b,b=4−2=2a=b=2B.

1C13e,1log,1ttstt−=11t−2e1s−13t01s13t−01sC.2AA.3Bn=24,S=24n=16,S=40n=8,S=48n=0,S=48,S=48-1=47,S=47,B.4C,C5Cx=22x=33x=55

x=66x=77x=99x=1010x=1111x=131311.C.1.C1,2018,2018,inS===020182017Sx=+2017n=()2000020182017201820172016Sxxxx=+=++2016n=n=2018i−C.

21381,1xy==220,1,2zxyxy=+===320,2,3zxyxy=+===520,3,5zxyxy=+===820,5,8zxyxy=+===1320,8,13zxyxy=+===132120,8yzxyx=+==138138.