高考化学一轮优化探究练习:章末排查练(六) (含解析)

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章末排查练(六)一、原电池电极反应式或总反应式的书写1.铁镍电池(负极-Fe,正极-NiO2,电解液-KOH溶液)已知:Fe+NiO2+2H2O放电充电Fe(OH)2+Ni(OH)2,则:负极:____________________

____________________________________________________;正极:________________________________________________________________________;阴极:______

__________________________________________________________________;阳极:________________________________

________________________________________。答案:Fe-2e-+2OH-===Fe(OH)2NiO2+2H2O+2e-===Ni(OH)2+2OH-Fe(OH)2+2e-===Fe

+2OH-Ni(OH)2-2e-+2OH-===NiO2+2H2O2.LiFePO4电池(正极-LiFePO4,负极-Li,含Li+导电固体为电解质)已知:FePO4+Li放电充电LiFePO4,则负极:__

______________________________________________________________________;正极:__________________________________________________________________

______;阴极:________________________________________________________________________;阳极:__________________

______________________________________________________。答案:Li-e-===Li+FePO4+Li++e-===LiFePO4Li++e-===LiLiFePO4-e-===FePO4+Li+3.高铁电池(负极-Zn

,正极-石墨,电解质为浸湿的固态碱性物质)已知:3Zn+2K2FeO4+8H2O放电充电3Zn(OH)2+2Fe(OH)3+4KOH,则:负极:________________________________________________

________________________;正极:________________________________________________________________________

;阴极:________________________________________________________________________;阳极:___________________________________________________________________

_____。答案:3Zn-6e-+6OH-===3Zn(OH)22FeO2-4+6e-+8H2O===2Fe(OH)3+10OH-3Zn(OH)2+6e-===3Zn+6OH-2Fe(OH)3-6e-+10OH-===2FeO2-4+8H2O4.氢氧燃料电池(1)电解质是KOH溶液(碱性电

解质)负极:________________________________________________________________________;正极:_____________________________________________________________

___________;总反应方程式:________________________________________________________________________。(2)电解质是H2S

O4溶液(酸性电解质)负极:________________________________________________________________________;正极:_____________________________________________

___________________________;总反应方程式:________________________________________________________________________。(3)电解质是NaCl溶液(中性电解质)负极:________

________________________________________________________________;正极:__________________________________________________________________

______;总反应方程式:________________________________________________________________________。答案:(1)2H2-4e-+4OH-===4H2OO2+2H2O+4e-===4OH-2H2+O

2===2H2O(2)2H2-4e-===4H+O2+4H++4e-===2H2O2H2+O2===2H2O(3)2H2-4e-===4H+O2+2H2O+4e-===4OH-2H2+O2===2H2O5.甲烷燃料电池(铂为两极,正极通入O2和CO2,负极通入甲烷,电解液有三种)(

1)电解质是熔融碳酸盐(K2CO3或Na2CO3)正极:________________________________________________________________________;负极:_____

___________________________________________________________________;总反应方程式:_______________________________________________________

_________________。(2)酸性电解质(电解液为H2SO4溶液)正极:________________________________________________________________________;负极:____________________________

____________________________________________;总反应方程式:________________________________________________________________________。(3)碱性电解质(电解液为KOH溶液)

正极:________________________________________________________________________;负极:_____________________________________________________________________

___;总反应方程式:________________________________________________________________________。答案:(1)2O2+8e-+4CO2===4CO2-3CH4

-8e-+4CO2-3===5CO2+2H2OCH4+2O2===CO2+2H2O(2)2O2+8e-+8H+===4H2OCH4-8e-+2H2O===CO2+8H+CH4+2O2===CO2+2H2O(3)2O2+8e-+4H2O===8

OH-CH4-8e-+10OH-===CO2-3+7H2OCH4+2O2+2OH-===CO2-3+3H2O6.甲醇燃料电池(1)碱性电解质(铂为两极,电解液为KOH溶液)正极:___________________

_____________________________________________________;负极:_____________________________________________________________

___________;总反应方程式:________________________________________________________________________。(2)酸性电解质(铂为两极,电解液为H2SO4溶液)正极:_________________________

_______________________________________________;负极:________________________________________________________________________;总反应方程式:_______________

_________________________________________________________。答案:(1)3O2+12e-+6H2O===12OH-2CH3OH-12e-+16OH-===2CO2-3+12H2O2CH3OH+3O2+4KOH===

2K2CO3+6H2O(2)3O2+12e-+12H+===6H2O2CH3OH-12e-+2H2O===12H++2CO22CH3OH+3O2===2CO2+4H2O7.CO燃料电池(总反应方程式均为2CO+O2===

2CO2)(1)熔融盐(铂为两极,Li2CO3和Na2CO3的熔融盐做电解质,CO为负极燃气,空气与CO2的混合气为正极助燃气)正极:________________________________________________________________________;负极:______

__________________________________________________________________。(2)酸性电解质(铂为两极,电解液为H2SO4溶液)正极:___________________________________________

_____________________________;负极:________________________________________________________________________。答案:(1)O2+4e-+2CO2===2CO2-32CO+2CO

2-3-4e-===4CO2(2)O2+4e-+4H+===2H2O2CO-4e-+2H2O===2CO2+4H+二、电解池电极反应式和总反应式的书写1.用惰性电极电解下列溶液(1)NaCl溶液阴极:_____

___________________________________________________________________;阳极:____________________________________________________________

____________;总反应式:________________________________________________________________________。(2)CuSO4溶液阴极:_______________________________

_________________________________________;阳极:________________________________________________________________________;总反应式:_______

_________________________________________________________________。答案:(1)2H++2e-===H2↑2Cl--2e-===Cl2↑2NaCl+2H2O=====电解2NaOH+H2↑+Cl2

↑(2)2Cu2++4e-===2Cu4OH--4e-===2H2O+O2↑2CuSO4+2H2O=====电解2Cu+2H2SO4+O2↑2.用惰性电极电解下列熔融态物质(1)MgCl2阳极:____________________________________

____________________________________;阴极:________________________________________________________________________;总反应式:____________________

____________________________________________________。(2)Al2O3阳极:________________________________________________________________________;阴极:________

________________________________________________________________;总反应式:_________________________________________________

_______________________。答案:(1)2Cl--2e-===Cl2↑Mg2++2e-===MgMgCl2(熔融)=====电解Mg+Cl2↑(2)6O2--12e-===3O2↑4Al3++12e-===4Al2Al2O3(熔融)=====电解冰晶石4Al

+3O2↑3.用铜做电极电解下列溶液(1)H2SO4溶液阴极:________________________________________________________________________;阳极:_______

_________________________________________________________________;总反应式:_______________________________________

_________________________________。(2)NaOH溶液阴极:________________________________________________________________

________;阳极:________________________________________________________________________;总反应式:____________________

____________________________________________________。答案:(1)2H++2e-===H2↑Cu-2e-===Cu2+Cu+H2SO4=====电解CuSO4

+H2↑(2)2H2O+2e-===H2↑+2OH-Cu-2e-+2OH-===Cu(OH)2↓Cu+2H2O=====电解Cu(OH)2↓+H2↑4.用Al做电极电解下列溶液(1)H2SO4溶液阴极:________________________________

________________________________________;阳极:_________________________________________________________________

_______;总反应式:________________________________________________________________________。(2)NaOH溶液阴极:________________________

________________________________________________;阳极:_________________________________________________________________

_______;总反应式:________________________________________________________________________。答案:(1)6H++6e-=

==3H2↑2Al-6e-===2Al3+2Al+3H2SO4=====电解Al2(SO4)3+3H2↑(2)6H2O+6e-===3H2↑+6OH-2Al-6e-+8OH-===2AlO-2+4H2O2Al+2H2O+2NaOH=====电解2NaAlO2

+3H2↑

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