【文档说明】人教版数学八年级上册15.2.2《分式的加减》课时练习(教师版).doc,共(3)页,75.500 KB,由MTyang资料小铺上传
转载请保留链接:https://www.ichengzhen.cn/view-21477.html
以下为本文档部分文字说明:
2023年人教版数学八年级上册15.2.2《分式的加减》课时练习一、选择题1.计算1a+1b的结果是()A.b+aB.1a+bC.2a+bD.a+bab【参考答案】答案为:D.2.化简的结果是()A.-x-yB.y-xC.x-yD.x+y【参考答案
】答案为:A3.化简m2m-3-9m-3的结果是()A.m+3B.m-3C.-2m+3D.4m-3【参考答案】答案为:A.4.已知,则的值是()A.12B.﹣12C.2D.﹣2【参考答案】答案为:D5.当+=2时,代数式的值
为()A.﹣2B.2C.﹣1D.1【参考答案】答案为:D6.已知,则的值为()A.0.5B.﹣0.5C.2D.﹣2【参考答案】答案为:B.7.对于非零的实数a、b,规定a⊕b=1b-1a.若2⊕(2x-1)=1,则x=()A.56B.54
C.32D.-16【参考答案】答案为:A8.若xy=x﹣y≠0,则分式=()A.B.y﹣xC.1D.﹣1【参考答案】答案为:C9.化简a2a-1-(a+1)的结果是()A.1a-1B.-1a-1C.2a-1a-1D.-2a-1a-1【参考答案】答案为:A.10.下列式子计算错误的是
()A.0.2a+b0.7a-b=2a+b7a-bB.x3y2x2y3=xyC.a-bb-a=-1D.1c+2c=3c【参考答案】答案为:A11.已知x2+5x+1=0,则x+1x的值为()A.5B.1C.﹣5
D.﹣1【参考答案】答案为:C12.已知a2-3a+1=0,则分式a2a4+1的值是()A.3B.13C.7D.17【参考答案】答案为:D.二、填空题13.化简:a2a-b-b2a-b=.【参考答案】答案为:a+b.14.化简:=.【
参考答案】答案为:1.15.计算12a2-9+23-a的结果是________.【参考答案】答案为:-2a+316.已知1a-1b=12,则aba-b的值是________.【参考答案】答案为:-2;17.已知a2+3ab+b2=0(a≠0,b≠0),则式子ba+ab的值等
于.【参考答案】答案为:-3.18.若1(2n-1)(2n+1)=a2n-1+b2n+1,对任意自然数n都成立,则a=____,b=____;【参考答案】答案为:12,-12.三、解答题19.化简:2x+y3x2y+x-2y3x2y-x-y3x2y.【参考答案】解:原式=2x+
y+x-2y-x+y3x2y=2x3x2y=23xy.20.化简:1x-1x-1;【参考答案】解:原式=x-1-xx(x-1)=-1x(x-1)=-1x2-x.21.化简:2221442aaa.【参考答案】解:原式=2
1a.22.化简:4214144122xxxx.【参考答案】解:原式=2)2(24xx.四、解答题23.先化简,再求值:2ba2-b2+1a+b,其中a=3,b=1;【参考答案】解:原式=1a-b.当a=3,b=1时,原式=13-1=12.24.已知1
x-1y=3,求分式2x-3xy-2yx+2xy-y的值.【参考答案】解:由已知条件可知,xy≠0.原式=(2x-3xy-2y)÷(-xy)(x+2xy-y)÷(-xy)=2(1x-1y)+3(1x-1y)-2.∵1x-1y=3.∴原式=2×3+33-2=9.25.化简
aa2-4·a+2a2-3a-12-a,并求值,其中a与2,3构成△ABC的三边,且a为整数.【参考答案】解:原式=a(a+2)(a-2)·a+2a(a-3)+1a-2=1+a-3(a-2)(a-3)=a-2(a-2)(a-3)=1
a-3,∵a与2,3构成△ABC的三边,且a为整数,∴1<a<5,即a=2或3或4,当a=2或a=3时,原式没有意义,∴a=4.则a=4时,原式=1.